Remove multiple entries from list python on basis of other list of objects
Question:
I have a scenario I have a array like ['abc' , 'def' , 'cdc'] and a list of object like [{'key': 'abc'} , {'key':'cdc'} ] so now I want to delete only strings from array which I have in key of list of objects .
currently trying this n = [x for x in n if x != 'abc'] but this is for single and don’t seems good way to iterate everytime . so what can be best and effective solution here ?
Answers:
Try this:
n= ['abc' , 'def' , 'cdc']
d = [{'key': 'abc'} , {'key':'cdc'}]
print([x for x in n if x not in [value['key'] for value in d]])
Output
['def']
[value[‘key’] for value in d] is the extracted keys from the list of objects (or rather… dictionaries in Python lingo)
I have a scenario I have a array like ['abc' , 'def' , 'cdc'] and a list of object like [{'key': 'abc'} , {'key':'cdc'} ] so now I want to delete only strings from array which I have in key of list of objects .
currently trying this n = [x for x in n if x != 'abc'] but this is for single and don’t seems good way to iterate everytime . so what can be best and effective solution here ?
Try this:
n= ['abc' , 'def' , 'cdc']
d = [{'key': 'abc'} , {'key':'cdc'}]
print([x for x in n if x not in [value['key'] for value in d]])
Output
['def']
[value[‘key’] for value in d] is the extracted keys from the list of objects (or rather… dictionaries in Python lingo)