How to seperate the values of a dictionary to space

Question

I have a dictionary, and I am using this code to print its first 3 key—value pairs.

[print(v) for i, v in enumerate(dict_data.items()) if i < 2]

Output:
(1, ['qd inc', 'san diego', '11578 sorrento valley road'])
(2, ['argon jg hannoosh', 'phil mag', 'initiation crazes polystyrene'])

I want to split the values of each key into the space, so my desired output is:

Desired Output: 

(1, ['qd', 'inc', 'san', 'diego', '11578', 'sorrento', 'valley', 'road'])
(2, ['argon', 'jg', 'hannoosh', 'phil', 'mag', 'initiation', 'crazes', 'polystyrene'])

I tried running this code but I get an error! (AttributeError: ‘list’ object has no attribute ‘split’)

dict_data = {key: [int(val) for val in value.split()] for key, value in dict_data.items()}

Asked By: Nick15

||

Source

Answer 1

Try this:

new_dict = {}
for key, value in dict_data.items():
    for phrase in value:
        new_dict.setdefault(key, []).extend(phrase.split())

Answered By: Anentropic

Answer 2

IIUC, If Your input dict be like below, You can use itertools.chain.from_iterable.

from itertools import chain

dct = { 
    1 : ['qd inc', 'san diego', '11578 sorrento valley road'] , 
    2 : ['argon jg hannoosh', 'phil mag', 'initiation crazes polystyrene']
}

res = {k: list(chain.from_iterable([st.split() for st in v])) for k,v in dct.items()}
print(res)

{
    1: ['qd', 'inc', 'san', 'diego', '11578', 'sorrento', 'valley', 'road'], 
    2: ['argon', 'jg', 'hannoosh', 'phil', 'mag', 'initiation', 'crazes', 'polystyrene']
}

Answered By: I'mahdi

How to seperate the values of a dictionary to space

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