counting unbeaten games n Python

Question

I’m creating a dataset for the FiFa worldcup 2022 and I’m trying to create a column that counts the number of matches a given country is unbeaten (i.e. has only won or drawn in previous matches) before the start of a given match.

I’ve been trying to get the logic going using a counter that loops over a list of results, but I can’t get it to work on a team level.

My desired output would look something like this:

Date	Team	Result	Desired output
2021-06-27	NL	lose
2021-09-01	NL	win	0
2021-09-04	NL	win	1
2021-09-08	NL	win	2
2021-09-15	NL	draw	3
2021-09-18	NL	Lose	4
2021-10-01	NL	Win	0
2021-10-05	NL	Win	1
2021-06-27	UK	lose
2021-09-01	NL	win	0
2021-09-04	UK	draw	1
2021-08-27	UK	lose	2
2021-08-31	UK	win	0

Asked By: brenda89

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Answer 1

I believe the provided output is incorrect as NL is still unbeaten on 2021-09-01.

I would thus use:

group = df['Result'][::-1].str.lower().eq('lose').groupby(df['Team']).cumsum()

df['days_unbeaten'] = df.groupby([df['Team'], group]).cumcount()

output:

          Date Team Result  Desired output  days_unbeaten
0   2021-06-27   NL   lose             NaN              0
1   2021-09-01   NL    win             0.0              0
2   2021-09-04   NL    win             1.0              1
3   2021-09-08   NL    win             2.0              2
4   2021-09-15   NL   draw             3.0              3
5   2021-09-18   NL   Lose             4.0              4
6   2021-10-01   NL    Win             0.0              0
7   2021-10-05   NL    Win             1.0              1
8   2021-06-27   UK   lose             NaN              0
9   2021-09-01   NL    win             0.0              2
10  2021-09-04   UK   draw             1.0              0
11  2021-08-27   UK   lose             2.0              1
12  2021-08-31   UK    win             0.0              0

Answered By: mozway

counting unbeaten games n Python

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