How to query a nested tuple by index using a list to represent the index?

Question

Get the value of a nested tuple at certain index like so:

tup = ((-3, (6, 15), 3), -9, ((-3, -6, 9, -5), -2))
    
print(tup[0][1][1])
>> 15

Want to query a nested tuple by index using as a list to represent the index, something like:

def getTupValue(input_tuple, input_list=[])
    ## returns the value at for example: tup[0][1][1]

getTupValue(tup, [0, 1, 1])
## returns 15

Asked By: eNath

||

Source

Answer 1

If you’re sure that there won’t be index errors, you can simply do:

def get_by_indexes(tup, indexes):
    for index in indexes:
        tup = tup[index]
    return tup


mytuple = ((-3, (6, 15), 3), -9, ((-3, -6, 9, -5), -2))
print(get_by_indexes(mytuple, [0, 1, 1]))

Output:

Answered By: funnydman

Answer 2

You can use functools.reduce:

from functools import reduce

tup = ((-3, (6, 15), 3), -9, ((-3, -6, 9, -5), -2))


def getTupValue(input_tuple, input_list):
    return reduce(lambda x, y: x[y], input_list, input_tuple)


print(getTupValue(tup, [0, 1, 1]))

Prints:

Answered By: Andrej Kesely

Answer 3

def getTupValue(input_tuple, input_list: list=None):
    if input_list in [None, []]:
        return input_tuple
    return getTupValue(input_tuple[input_list.pop(0)], input_list)
tup = ((-3, (6, 15), 3), -9, ((-3, -6, 9, -5), -2))
getTupValue(tup, input_list=[0,1,1])

Answered By: MoRe

How to query a nested tuple by index using a list to represent the index?

Question:

Answers: