What should I add or what other way is there?

Question

I have a dictionary:

test1 = {"SN": "SN: abc123rnMAC: 10:ab:cd:30:5C:7Crn01-04-2022 Замена"}

I wrote a regular expression in the code:

name_match_3 = re.search(r"(rn.+)", test1.get("SN"), flags=re.DOTALL)
dict_miner_regular["Comment"] = (name_match_3.group(1) if name_match_3 else None)

As a result, I’m getting:

result_2 = {"Comment": "MAC: 10:ab:cd:30:5C:7Crn01-04-2022 Замена"}

But I also need to remove MAC: 10:ab:cd:30:5C:7C. But it’s not everywhere.

As a result, it is necessary to remove SN: and MAC:

result_3 = {"Comment": "01-04-2022 Замена"}

I understand that something needs to be added here –> r"(rn.+)"

Asked By: Alexey

||

Source

Answer 1

If SN and MAC are always directed at the start of a string, then use

rn(.+)$

Python Example

import re

test = {"SN": "SN: abc123rnMAC: 10:ab:cd:30:5C:7Crn01-04-2022 Замена"}
match = re.search(r"rn(.+)$", test.get("SN"))
result = {"Comment": match.group(1) if match else None}  # {'Comment': '01-04-2022 Замена'}

Edit

Otherwise, you can use the following regex

(?:^|rn)((?:(?!SN|MAC|rn).)+)

You can add other keys next to SN and MAC as well.

See the regex demo

Answered By: Artyom Vancyan

Answer 2

if it you need element after last rn then you can do it with split() and [-1] without regex

result = {"Comment": test1["SN"].split("rn")[-1] }

Full example

test1 = {"SN": "SN: abc123rnMAC: 10:ab:cd:30:5C:7Crn01-04-2022 Замена"}
result = {"Comment": test1["SN"].split("rn")[-1] }
print(result)

Result:

{'Comment': '01-04-2022 Замена'}

Answered By: furas

What should I add or what other way is there?

Question:

Answers:

Python Example

Edit