How can I split my string and delete the first item for every row in my dataframe? key error 18

Question

I keep getting key error 18 and dont know how to solve it. I am trying to split the values of a column and delete the first element of the list.

This is my code:

 last_name= []

for i in train.index:

#Split at space and delete the first name  

   name_id = test_df_bin['Name'][i].split(' ')
   del name_id[0]

 #list of last name
   last_name.append(name_id[0])


test_df_bin['Surname'] = last_name`

*Error messege:

KeyError Traceback (most recent call last)
File ~Anacondalibsite-packagespandascoreindexesbase.py:3621, in Index.get_loc(self, key, method, tolerance)
3620 try:
-> 3621 return self._engine.get_loc(casted_key)
3622 except KeyError as err:

KeyError: 18*

Asked By: Efan Mutembo

||

Source

Answer 1

I strongly suggest against looping unless strictly necessary. In this case you can achieve your desired solution with:

test_df_bin['Surname'] = test_df_bin['Name'].str.split().str[1:]

If you’d like the output of the split() joined back into a single string, then:

test_df_bin['Surname'] = [' '.join(x) for x in test_df_bin['Name'].str.split().str[1:]]

Answered By: Celius Stingher

How can I split my string and delete the first item for every row in my dataframe? key error 18

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