location of member in list of dictionaries
Question:
if I have the following:
[{'place':1, 'acc':75}, {'place':2, 'acc':95}, {'place':3, 'acc':60}]
What would be the best way to get the value of the place which has the best accuracy ?
In this example the result would be: 2
Answers:
It would be easier to use a list of lists. For example:
[[75, 1], [95, 2], [60, 3]]
For added convenience, perhaps organise them as [accuracy, place] instead of [place, accuracy]. Then you can iterate through the lists using a for loop and check each value, changing the current best place with each higher accuracy.
Edit: reading python tutorials and guides can also aid you in the future
The built-in max function allows you to specify a key. So, for your example, you could do this:
list_ = [{'place':1, 'acc':75}, {'place':2, 'acc':95}, {'place':3, 'acc':60}]
print(max(list_, key=lambda x: x['acc'])['place'])
Output:
2
if I have the following:
[{'place':1, 'acc':75}, {'place':2, 'acc':95}, {'place':3, 'acc':60}]
What would be the best way to get the value of the place which has the best accuracy ?
In this example the result would be: 2
It would be easier to use a list of lists. For example:
[[75, 1], [95, 2], [60, 3]]
For added convenience, perhaps organise them as [accuracy, place] instead of [place, accuracy]. Then you can iterate through the lists using a for loop and check each value, changing the current best place with each higher accuracy.
Edit: reading python tutorials and guides can also aid you in the future
The built-in max function allows you to specify a key. So, for your example, you could do this:
list_ = [{'place':1, 'acc':75}, {'place':2, 'acc':95}, {'place':3, 'acc':60}]
print(max(list_, key=lambda x: x['acc'])['place'])
Output:
2