How to make a tiebreaker on Turtle Race?

Question

Hey guys I am doing the turtle race module on 100 days of code and I have been able to get it to work so far. However I am having trouble coding a tiebreaker function into it.
I used boolean based "if" statements to make a rudimentary tiebreaker but it only works if your guess in the game is one of the two winners. If there is a tie and neither one of the winners are your guess I can only get it to say "You lost."
Does anyone have any idea on how I can code this a little better?

from turtle import Turtle, Screen
import random

is_race_on= False

screen = Screen()
screen.setup(500, 400)
user_bet = screen.textinput(title="Make your 
bet",prompt= "Which turtle will win the race? 
Enter a color: ")
colors = ['red', 'orange', 'yellow', 'green', 
'blue', 'purple']
y_positions= [-125, -75, -25, 25, 75, 125]
all_turtles= []

for turtle_index in range(0, 6):
    new_turtle = Turtle()
    new_turtle.color(colors[turtle_index])
    new_turtle.penup()
    new_turtle.shape("turtle")
    new_turtle.goto(x= -230, y= 
y_positions[turtle_index])
    new_turtle.pendown()
    all_turtles.append(new_turtle)

win = False
lose = False
if user_bet:
    is_race_on = True

while is_race_on:


    for turtle in all_turtles:
        if turtle.xcor() > 230:
            is_race_on= False
            winning_color = turtle.pencolor()
            if winning_color == user_bet:
                win = True
                win_color = winning_color

             

            else:
                lose = True
                lose_color = winning_color

            
        if win and lose == True:
            print(f"There was a tie between 
{win_color}, and {lose_color}")


        elif win == True and lose == False:
            print(f"You've Won!! The {win_color} 
turtle is the winner!")

    elif win == False and lose == True:
        print(f"You lost you loser you! The {lose_color} turtle is the winner!!")



    random_distance= random.randint(0, 10)
    turtle.forward(random_distance)


screen.exitonclick()

Asked By: Cameron

||

Source

Answer 1

I would order this a little different. Beginning of the while loop I would check the position of each turtle and any turtle that’s crossed the finish line I would save to a winners list. If the length of the list is 0, then no one has won. You can then loop through the turtles again, incrementing them, and start again. If a turtle HAS won and the size of the list is 1, you can pay out that winner. If the list is > 1 you have a tie and can deal with that as you see fit. This causes you to loop through the turtles twice but organizes yourself a bit better. Hopefully this makes sense.

Answered By: Wumbo

How to make a tiebreaker on Turtle Race?

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