Python seperate numbers where no obvious seperation symbol is vissible
Question:
I have a text file that I am trying to turn into something I can do math operations with.
The issue with the file is that some numbers are not seperated correctly like the following:
mylist = ['21', '0', '0-2.0000000000000E-001-6.0000000000000E+001']
Right now I have everything as a string and want to convert it to a float but before doing so I need seperate the last three numbers to get the following output:
mylist = ['21', '0', '0' , '-2.0000000000000E-001' , '-6.0000000000000E+001']
I need something that seperates the item in the list when a minus sign is present, except when the minus sign is preceded by E.
Answers:
It should be checked against a few more examples, but a regular expression can do the trick:
>>> from re import findall
>>> findall(r'[+-]?d+(?:.d+)?(?:E[+-]d+)?', ' '.join(mylist))
['21', '0', '0', '-2.0000000000000E-001', '-6.0000000000000E+001']
I have a text file that I am trying to turn into something I can do math operations with.
The issue with the file is that some numbers are not seperated correctly like the following:
mylist = ['21', '0', '0-2.0000000000000E-001-6.0000000000000E+001']
Right now I have everything as a string and want to convert it to a float but before doing so I need seperate the last three numbers to get the following output:
mylist = ['21', '0', '0' , '-2.0000000000000E-001' , '-6.0000000000000E+001']
I need something that seperates the item in the list when a minus sign is present, except when the minus sign is preceded by E.
It should be checked against a few more examples, but a regular expression can do the trick:
>>> from re import findall
>>> findall(r'[+-]?d+(?:.d+)?(?:E[+-]d+)?', ' '.join(mylist))
['21', '0', '0', '-2.0000000000000E-001', '-6.0000000000000E+001']