convert file with multiple lines into array

Question

How can I convert a file like:

ap-southeast-1
ap-southeast-2
ca-central-1

into:

"ap-southeast-1","ap-southeast-2","ca-central-1"

What I tried so far:


sed -z 's/n/,/g;s/,$/n/'  filename

Above gives:

ap-southeast-1,ap-southeast-2,ca-central-1

Tries xls transpose function but that also no luck: https://support.microsoft.com/en-us/office/transpose-function-ed039415-ed8a-4a81-93e9-4b6dfac76027

Asked By: Kiran Kumar

||

Source

Answer 1

Extending OP’s current sed:

$ sed -z 's/n/,/g;s/^/"/;s/,$/"n/;s/,/","/g'  filename
"ap-southeast-1","ap-southeast-2","ca-central-1"

One awk idea:

$ awk '{out=out sep $0; sep="",""} END {print """ out """}' filename
"ap-southeast-1","ap-southeast-2","ca-central-1"

Answered By: markp-fuso

Answer 2

data = []

with open('original-file.txt', 'r') as o:
    for line in o:
      data.append(f'"{line.strip()}"')

with open('new-file.txt', 'w') as n:
    n.write(','.join(data))

$ cat original-file.txt
example-country-1
example-country-2
example-country-3

$ python3 script.py && cat new-file.txt
"example-country-1","example-country-2","example-country-3"

Answered By: omermikhailk

Answer 3

You included the python tag so I’ll answer with python code.

Try this:

new = []
with open("/path/to/your/file") as f:
    for line in f:
        new.append(f"{line.strip()}")
with open("/path/to/file/to/write", "w") as f: #this can be the same file, but be sure you have write access
    f.write('"' + '","'.join(new) + '"')

This can be written better but it works for a one-off script.

Edit – welp by the time I’ve written my answer someone already answered with a similar answer.

Answered By: Stefan Šućur

Answer 4

Using sed

$ sed -Ez 's/([[:alnum:]-]*)n/"1",/g;s/,$/n/' input_file
"ap-southeast-1","ap-southeast-2","ca-central-1"

Answered By: HatLess

convert file with multiple lines into array

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