values lower than 10 in python dictionary

Question

hello there I want to get the values in dict which are lower than number 10 and count them , here is my code.

my code :

counter = 0
dict = {'one': [3, 9, 5, 13], 'two': [6]}

    for values in dict :
        if dict.values() < 10 :
            counter = counter + 1

the output should be like counter = 4 if we print out counter but i dont how to compare it .

Asked By: ImThePeak

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Source

Answer 1

An efficient way to do it is a generator comprehension that flattens the nested .values() of the dictionary and counts them using sum. It is similar to @matszwecja‘s comment, but potentially faster because it doesn’t store the values in a list.

my_dict = {'one': [3, 9, 5, 13], 'two': [6]}
counter = sum(1 for values in my_dict.values() for v in values if v < 10)

Answered By: fsimonjetz

Answer 2

counter = 0
d_ = {'one':[3,9,5,13], 'two':[6]}
for ki, Lb in d_.items():
    for b_ in Lb:
        if b_ < 10:
            counter += 1

Answered By: adbiLenLa

Answer 3

res = []
[res.extend(sub) for sub in dict.values()]
print(len([num for num in res if num < 10]))

Answered By: lroth

values lower than 10 in python dictionary

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