Comparing two values every n second and run a code based on the current and previous compared results in a while loop in python

Question

Here is something I am trying to do:

A is a value that is constantly changing, and B is a fixed value

compare A and B every 5 seconds
if A > B, do something
if A < B, do something else
but if the current compared result is the same as the previous one (like if the current result is A > B, and the previous result is also A > B), do nothing until the result changes.
repeat

I really don’t know what to do with the 4th one, could somebody give me a hint?

Huge thanks

Asked By: ckx_9199

||

Source

Answer 1

Store the previous comparision in a variable.

previousComparison = '';
    while True:
     time.sleep(5) # Sleep for 5 seconds
     if a > b and previousComparision != 'AIsGreater':
      #do 2.
      previousComparision = 'AIsGreater'
     if b > a and previousComparision = 'BIsGreater':
      #do 3.
      #previousComparision = 'BIsGreater'

Answered By: S4RUUL

Answer 2

You can just remember the previous value of B and compare it as well to determine if you need to do something

def update(val):
   return (val + 7) % 1000 # example

A = 500
B = 0
previous_B = 100000

while True:
    previous_B = B
    B = update(B)
    if previous_B < A and B > A:
        print(B, 'Do something')
    elif previous_B > A and B < A:
        print(B, 'Do something else')

Answered By: Alexey Larionov

Answer 3

In order to do this, you can keep track of the previous result in an additional variable

import random
previous = None
a = 10
b = 2

i = 0
while(i < 20):
    print (a, b)
    if (a > b and previous != False):
        print('do something')
    elif (a < b and previous == False):
        print('do something else')
    previous = a < b
    b = random.randint(0, 20)

    i += 1

Answered By: Bram

Answer 4

As you have not mentioned any language preference, I am using python here.

import time
c = time.time()

if A>B:
    state = True
    ''' Do the initial action for this state'''
elif A<B:
    state = False
    ''' Do the initial action for this state'''
while True:
    if (time.time() - c) >= 5:
        c = time.time()
        A = check_A() # some dummy function for illustration purpose
        B = check_B() # some dummy function for illustration purpose
        if A>B:
            if not state:
                state = True
                ''' Do something that you like '''
        elif A<B:
            if state:
                state = False
                ''' Do something that you like '''

Here I have assumed that you do not want anything to happen when when A==B. The logic here that unless the state changes there will be no action for that particular state.

If here you do not want your code to be continuously running then you can use time.sleep(SLEEP_TIME).

import time

if A>B:
    state = True
    ''' Do the initial action for this state'''
elif A<B:
    state = False
    ''' Do the initial action for this state'''
while True:
    time.sleep(5)
    A = check_A() # some dummy function for illustration purpose
    B = check_B() # some dummy function for illustration purpose
    if A>B:
        if not state:
            state = True
            ''' Do something that you like '''
    elif A<B:
        if state:
            state = False
            ''' Do something that you like '''

Answered By: MURTUZA BORIWALA

Comparing two values every n second and run a code based on the current and previous compared results in a while loop in python

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