How to print out the item of a list when its corresponding value in another list is the biggest?

Question

If I have 2 lists:

values = ['a', 'b', 'c', 'd']
accuracies = [1, 2, 3, 4]

I want to return the value in values when its corresponding accuracy in accuracies is the biggest.
In this case, the result of value should be 'd', because its corresponding accuracy is 4.
Is there a way to do it in python?
Thank you in advance.

Asked By: Bella

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Source

Answer 1

Use this:

In [5]: values[accuracies.index(max(accuracies))]
Out[5]: 'd'

Answered By: Mehrdad Pedramfar

Answer 2

Iterate through the accuracies list and find the largest value. Every time you find a larger value make sure to keep track of the "index" in which it occurs. If 4 is the largest value your program should know that index 3 is where the largest value is in accuracies. Once you have the index of the largest element, simply access values in the same spot.

values = ['a', 'b', 'c', 'd'] 
accuracies = [1, 2, 3, 4]

max_val = float('-inf')
max_val_index = 0
for index, acc in enumerate(accuracies):
    if acc > max_val:
        max_val = acc
        max_val_index = index

print(values[i])

Answered By: JRose

Answer 3

You can solve this by simply getting the max value the index of said value, then finding the equivalent in the values list

values[accuracies.index(max(accuracies))]

this returns in your case d

Answered By: Mateo Covacho

How to print out the item of a list when its corresponding value in another list is the biggest?

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