Datetime.strptime format for 2022-08-24T04:57:17.065000+00:00
Question:
We have the following string in a variable:
date_variable = "2022-08-24T04:57:17.065000+00:00"
We would like to convert this to datetime.
The following does not work:
timestamp_formatted = datetime.strptime(date_variable, '%Y-%m-%d%H:%M:%S.%f+%z')
Please help.
Answers:
You left out the T and %z includes the sign of the time zone offset so remove the +:
from datetime import datetime
date_variable = "2022-08-24T04:57:17.065000+00:00"
# ^
timestamp_formatted = datetime.strptime(date_variable, '%Y-%m-%dT%H:%M:%S.%f%z')
print(repr(timestamp_formatted))
Output:
datetime.datetime(2022, 8, 24, 4, 57, 17, 65000, tzinfo=datetime.timezone.utc)
We have the following string in a variable:
date_variable = "2022-08-24T04:57:17.065000+00:00"
We would like to convert this to datetime.
The following does not work:
timestamp_formatted = datetime.strptime(date_variable, '%Y-%m-%d%H:%M:%S.%f+%z')
Please help.
You left out the T and %z includes the sign of the time zone offset so remove the +:
from datetime import datetime
date_variable = "2022-08-24T04:57:17.065000+00:00"
# ^
timestamp_formatted = datetime.strptime(date_variable, '%Y-%m-%dT%H:%M:%S.%f%z')
print(repr(timestamp_formatted))
Output:
datetime.datetime(2022, 8, 24, 4, 57, 17, 65000, tzinfo=datetime.timezone.utc)