How to get name of derived class from base class

Question

I can get the name of a base class as follows:

>>> class Base(object):
...     pass
...
>>> class Derived(Base):
...     def print_base(self):
...         for base in self.__class__.__bases__:
...             print base.__name__
...
>>> foo = Derived()
>>> foo.print_base()
Base

In this example, how do I do the reverse and get the name of Derived from a function within Base? E.g:

>>> class Base(object):
...     def print_derived(self):
...         [pseudocode: return Derived class name]
...
>>> class Derived(Base):
...     pass
...
>>> bar = Derived()
>>> bar.print_derived()
Derived

I could obviously just print self.__class__.__name___ in Derived but I have a lot of unit tests inheriting Base as a mixin and I want to track which class called it from one adjustment to the Base mixin.

Asked By: alias51

||

Source

Answer 1

You just need to print self.__class__ in the Base method:

>>> class Base(object):
...     def print_derived(self):
...         print(self.__class__.__name__)
...
>>> class Derived(Base):
...     pass
>>> d = Derived()
>>> d.print_derived()
Derived

Answered By: Pranav Hosangadi

How to get name of derived class from base class

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