Multiple Search Terms in List
Question:
I’m looking to count whether eth or btc appear in listy
searchterms = ['btc', 'eth']
listy = ['Hello, my name is btc', 'hello, my name is ETH,', 'i love eth', '#eth is great', 'barbaric tsar', 'nothing']
cnt = round((sum(len(re.findall('eth', x.lower())) for x in listy)/(len(listy)))*100)
print(f'{cnt}%')
The solution only looks for eth. How do I look for multiple search terms?
Bottom line: I have a list of search terms in searchterms. I’d like to see if any of those appear in listy. From there, I can perform a percentage of how many of those terms appear in the list.
Answers:
I would say instead of complicating the problem and using re, use a simple classic list comprehension.
listy = ['Hello, my name is btc', 'hello, my name is ETH,', 'i love eth', '#eth is great', 'barbaric tsar', 'nothing']
print(len([i for i in listy if 'btc' in i.lower() or 'eth' in i.lower()]) * 100 / len(listy))
It improves the readability and the simplicity of the code.
Let me know if it helps!
you need to use the pipe "|" betwwen the values you want to search. In your code change re.findall('eth', x.lower() by re.findall(r"(eth)|(btc)", x.lower()
listy = ['Hello, my name is btc', 'hello, my name is ETH,', 'i love eth', '#eth is great', 'barbaric tsar', 'nothing']
cnt = round((sum(len(re.findall(r"(eth)|(btc)", x.lower())) for x in listy)/(len(listy)))*100)
print(f'{cnt}%')
67%
a bit more of code is giving a good readability. also adding additional words to search for, just needs to add them to the list search_for. for counting it uses a defaultdict.
listy = ['Hello, my name is btc', 'hello, my name is ETH,', 'i love eth', '#eth is great', 'barbaric tsar', 'nothing']
my_dict = defaultdict(int)
search_for = ['btc', 'eth']
for word in listy:
for sub in search_for:
if sub in word:
my_dict[sub] += 1
print(my_dict.items())
I’m looking to count whether eth or btc appear in listy
searchterms = ['btc', 'eth']
listy = ['Hello, my name is btc', 'hello, my name is ETH,', 'i love eth', '#eth is great', 'barbaric tsar', 'nothing']
cnt = round((sum(len(re.findall('eth', x.lower())) for x in listy)/(len(listy)))*100)
print(f'{cnt}%')
The solution only looks for eth. How do I look for multiple search terms?
Bottom line: I have a list of search terms in searchterms. I’d like to see if any of those appear in listy. From there, I can perform a percentage of how many of those terms appear in the list.
I would say instead of complicating the problem and using re, use a simple classic list comprehension.
listy = ['Hello, my name is btc', 'hello, my name is ETH,', 'i love eth', '#eth is great', 'barbaric tsar', 'nothing']
print(len([i for i in listy if 'btc' in i.lower() or 'eth' in i.lower()]) * 100 / len(listy))
It improves the readability and the simplicity of the code.
Let me know if it helps!
you need to use the pipe "|" betwwen the values you want to search. In your code change re.findall('eth', x.lower() by re.findall(r"(eth)|(btc)", x.lower()
listy = ['Hello, my name is btc', 'hello, my name is ETH,', 'i love eth', '#eth is great', 'barbaric tsar', 'nothing']
cnt = round((sum(len(re.findall(r"(eth)|(btc)", x.lower())) for x in listy)/(len(listy)))*100)
print(f'{cnt}%')
67%
a bit more of code is giving a good readability. also adding additional words to search for, just needs to add them to the list search_for. for counting it uses a defaultdict.
listy = ['Hello, my name is btc', 'hello, my name is ETH,', 'i love eth', '#eth is great', 'barbaric tsar', 'nothing']
my_dict = defaultdict(int)
search_for = ['btc', 'eth']
for word in listy:
for sub in search_for:
if sub in word:
my_dict[sub] += 1
print(my_dict.items())