How to get every n-th element from a multi-dimensional Python list?
Question:
From
lst = [ ['a', 1], ['b', 2] ]
How can I get a new list [1, 2] from it?
lst[0:2][1] works iteratively, so it doesn’t work.
Is that possible without any loops?
Answers:
you can use list comprehension
lst = [ ['a', 1], ['b', 2] ]
n=1
result=[i[n] for i in lst ]
#=>[1, 2]
Using map:
>>> from operator import itemgetter
>>> list(map(itemgetter(1), lst))
[1, 2]
From
lst = [ ['a', 1], ['b', 2] ]
How can I get a new list [1, 2] from it?
lst[0:2][1] works iteratively, so it doesn’t work.
Is that possible without any loops?
you can use list comprehension
lst = [ ['a', 1], ['b', 2] ]
n=1
result=[i[n] for i in lst ]
#=>[1, 2]
Using map:
>>> from operator import itemgetter
>>> list(map(itemgetter(1), lst))
[1, 2]