regex ":[^]" not working in python re module
Question:
I have a problem in regular expression using re module
pattern = ":[^]", string = ":r", and bool(re.findall(strting, pattern)) should return True However, it returns False like the pic1
I verified this using https://regexr.com/ and it shows like the pic2. So I believe the problem is on the re module
How can i show the same result of pic2 in python
Answers:
That’s the expected behavior cause re.findall(':r', ':[^]') means find the strings that match the pattern :r in the string :[^] i.e. the first argument is the pattern and second argument is the string/text where you need to find a match.
And [^] in python regex means none of the characters that’s inside the square brackets after caret ^ symbol should match.
If you are looking to find the strings starting with : followed by any number of alphabets, following should work:
>>> re.findall(':w+',':r')
[':r']
```
I have a problem in regular expression using re module
pattern = ":[^]", string = ":r", and bool(re.findall(strting, pattern)) should return True However, it returns False like the pic1
I verified this using https://regexr.com/ and it shows like the pic2. So I believe the problem is on the re module
How can i show the same result of pic2 in python
That’s the expected behavior cause re.findall(':r', ':[^]') means find the strings that match the pattern :r in the string :[^] i.e. the first argument is the pattern and second argument is the string/text where you need to find a match.
And [^] in python regex means none of the characters that’s inside the square brackets after caret ^ symbol should match.
If you are looking to find the strings starting with : followed by any number of alphabets, following should work:
>>> re.findall(':w+',':r')
[':r']
```