Django python – how do add new record every time I update the screen? instead it updates the existing record.?

Question

How do add new record every time I update the screen? instead it updates the existing record.?

Here are the models.

class Dealer(models.Model):
    city = models.CharField('City', max_length=30, blank=True, null=True)
    contact_name = models.CharField('Contact name', max_length=250, blank=True, null=True)
    dealer_id = models.CharField('dealer_id', max_length=50, primary_key=True)
    dealership_name = models.CharField('Dealership name', max_length=100, blank=True, null=True)
    dsr = models.CharField('DSR', max_length=50, blank=True, null=True)
    email = models.EmailField('Email', blank=True, null=True)
    fax = models.CharField('Fax', max_length=20, blank=True, null=True)
    dealer_notes = models.TextField('notes', blank=True, null=True)
    phone = models.CharField('Phone', max_length=20, blank=True, null=True)
    rating = models.CharField('Rating', max_length=20, blank=True, null=True)
    state = models.CharField('State', max_length=5, blank=True, null=True)
    street = models.CharField('Street', max_length=60, blank=True, null=True)
    zip = models.CharField('Zip', max_length=10, blank=True, null=True)

    def __str__(self):
        return self.dealer_id


class Activity(models.Model):    
    dealer_id = models.ForeignKey(Dealer, on_delete=models.CASCADE)
    activity_number = models.PositiveIntegerField(default=1)
    date_created = models.DateField('date created', blank=True, null=True)
    created_by = models.CharField('created_by', max_length=50, blank=True, null=True)
    type = models.CharField('state', max_length=50, blank=True, null=True)
    activity_notes = models.TextField(max_length=500, blank=True, null=True)

    def __str__(self):
        return f"{self.dealer_id} {self.activity_number}"

When it lands in dealer notes page it will get the details from the user to enter model fields and save.For each record there can be many number of activity notes. But when I tried to add a new note it updates the existing one, i want it create a new record.

def create_notes(request, dealer_id):
    item, _ = Activity.objects.get_or_create(dealer_id_id=dealer_id)    
    form = ActivityForm(instance=item)   
    if request.method == 'POST':
        form = ActivityForm(request.POST, instance=item)
       
        if form.is_valid():
            try:
                
                form.save()
            except:
                pass
        else:
            return redirect('dealernotes/' + request.post.get('dealer_id_id'))
    return render(request,
                  'dealernotes.html',
                  {'form': item,},
                  )
 Can you help to create a new note every time? by activity number i should be able to update as well. 
urls:

  path('dealernotes/<str:dealer_id>?/', views.update_notes,  name='dealernotes')

How do I fix this issue?

Asked By: DjangoNoob

||

Source

Answer 1

Don’t use get_or_create and instead just use create

item = Activity.objects.create(dealer_id_id=dealer_id)

Edit 2 (scraping Edit1)

Here, Try to restructure it so that Activity is only created when you submit the form.

Note: We’re changing the template, don’t forget about that

def create_notes(request, dealer_id):

    if request.method == 'POST':
        
        form = ActivityForm(request.POST)
       
        if form.is_valid():
            try:
                form.save()
            except:
                pass
        else:
            # debugging error:
            print(form.errors.as_data())

            return redirect('dealernotes/' + request.post.get('dealer_id_id'))

    dealerObj = Dealer.objects.get(pk=dealer_id)
    form = ActivityForm(initial={'dealer_id' : dealerObj})   
    data = {
        'form': form,
    }

    return render(request, 'dealernotes.html', data)

Template

We’re going to replace the PK input with a dealer_id, that way the form is valid on the post

<form action="" method="post">
    {% csrf_token %}
    {{ form }}
    <input type="submit" value="Submit">
</form>

Answered By: Nealium

Django python – how do add new record every time I update the screen? instead it updates the existing record.?

Question:

Answers:

Edit 2 (scraping Edit1)

Template