Python text replacement function

Question

I’m using this function to clean up my columns. However, somehow I’m deleting numbers, which I don’t want to do. So for example here, when applied, I get: "standard_access_requested_application_rolegroup_ld_e"

Any help would be great. Thanks.

def text_replacement(x):
  """
  This function formats the field names so that they are more SQL friendly
  """
  
  for key, value in custom_fields_dict.items():
    pattern = re.compile(key, re.IGNORECASE)
    x = pattern.sub(value, x).lower().replace('fields.','').replace(' ','_').replace('™','')
    x = re.sub(r"[()[]&^%$#@!-:'/]",'',x)
  return x

text_replacement("standard_access_requested_application:_'role/group': ]ld_10706(e)™")

The application of the function:

#Replace the columns in the dataframe
new_columns = []
for i in df.columns:
  new_columns.append(text_replacement(i))

df.columns = new_columns

Asked By: elia_Werner

||

Source

Answer 1

The !-: part of your pattern represents a character in the range between ! and :, which apparently includes digits.

If you put escape characters before !, - and :, this would work:

x = re.sub(r"[()[]&^%$#@!-:'/]", '', x)
[1]: 'standard_access_requested_application_rolegroup ld_10706e'

I only used the regex pattern, but not the rest of your code, so your own result may vary, but the digits would be saved.

Answered By: n.shabankin

Python text replacement function

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