How to write a code to get a user input for a 6 digit integer number and check if the number is palindrome?

Question

Write a python program to ask a user to input a 6-digit integer and check if the input is a palindrome or not. If the user fails to enter an integer or if the integer is less than 6-digit, the user must be asked to input it again.
(NOTE: The code should be written without using TRY and EXCEPT and the user should not be allowed to take more than 3 attempts.)

My take on this is:

for n in range(3):
    while True:
        i = input("Please enter a six digit integer:")
        if i.isnumeric():
            if len(i)==6:
                i_integer = int(i)
                print("Your number is:",i_integer,"and the data type is:",type(i_integer))
        break
    else:
        print("Enter value is not numeric")

With this code, if I enter a six-digit number, then I have to enter it for 3 times, instead of one time. Below is the output.

Please enter a six digit integer:123456
Your number is: 123456 and the data type is: <class 'int'>
Please enter a six digit integer:123456
Your number is: 123456 and the data type is: <class 'int'>
Please enter a six digit integer:123456
Your number is: 123456 and the data type is: <class 'int'>

Is there any better way to do this without using TRY and EXCEPT?

Asked By: Atif

||

Source

Answer 1

Instead of a "for" loop, you could just use a counter and "while" loop like the following code snippet.

tries = 0

while True:
    i = input("Please enter a six digit integer:")
    if i.isnumeric() and len(i) == 6:
        i_integer = int(i)
        print("Your number is:",i_integer,"and the data type is:",type(i_integer))
        break
    else:
        tries += 1
        if tries >= 3:
            break
            
if tries >= 3:
    print("Sorry - too many tries to enter a six digit integer")
    quit()
        
# Palindrome testing would start here
print("Going to see if this is a palindrome")

Testing this out, the following output was displayed on my terminal.

@Una:~/Python_Programs/Palindrome$ python3 Numeric.py 
Please enter a six digit integer:12345
Please enter a six digit integer:123456
Your number is: 123456 and the data type is: <class 'int'>
Going to see if this is a palindrome

I will leave it to you to build the test to see whether or not the entered number is a palindrome.

Give that a try.

Answered By: NoDakker

Answer 2

tries = 0

while True:
    i = input("Please enter a six digit integer:")
    if i.isnumeric() and len(i) == 6:
        i_integer = int(i)
        print("Your number is:",i_integer,"and the data type is:",type(i_integer))

        # Palindrome testing would start here
        print("Going to see if this is a palindrome")

        n=int(i)
        temp=n
        rev=0
        while(n>0):
            dig=n%10
            rev=rev*10+dig
            n=n//10
        if(temp==rev):
            print("The number is a palindrome!")
        else:
            print("The number isn't a palindrome!")        
        break

    else:
        tries += 1
        if tries >= 3:
            break

if tries >= 3:
    print("Sorry - too many tries to enter a six digit integer")

Answered By: Diaa

How to write a code to get a user input for a 6 digit integer number and check if the number is palindrome?

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