Sorting an array of Objects (Deck of Cards)

Question

I’m making a game in python with a deck of cards. I have an array of the cards I’ve created, and shuffled. I would like to be able to sort this array, both by value: {2,3,4,5,6,7,8,9,10,J,Q,K,A} and by their suit and corresponding values – same order of values. I have previously used the sort and sorted methods, however am unsure how to do this with an array of objects as I am getting the output: TypeError: ‘Card’ object is not subscriptable. How would I go about creating these sorting algorithims?

I have tried the following:
self.cards.sort(key=lambda x: x.value)
This sorts it the the order: {10,2,3,4,5,6,7,8,9,A,J,Q,K} I understand the alphabetical order this is sorted in, however am unsure why 10 is the first item listed.

I have also tried things like:
values=dict(zip(‘23456789TQKA’,range(2,15)))
but this seems to give me the error I have previously talked about.

Any help would be apricated! Thanks!

This is the code I currently have:

from random import randint

class Card:
def __init__(self, suit, value):
    self.suit = suit
    self.value = value

def show(self):
    print("{} - {}".format(self.value, self.suit))

class Deck:
size = 52
def __init__(self):
    self.cards = []
    self.build()

def build(self):
    for s in ["C", "D", "H", "S"]:
        for v in ["2", "3", "4", "5", "6", "7", "8", "9", "10", "J", "Q", "K", "A"]:
            self.cards.append(Card(s, v))

def show(self):
    for c in self.cards:
        c.show()

def shuffle(self):
    for i in range(self.size-1, 0, -1):
        r = randint(0, i + 1)
        self.cards[i], self.cards[r] = self.cards[r], self.cards[i]

#Sorting will go here

deck = Deck()
print("After creating The Deck")
deck.show()
deck.shuffle()
print("After Shuffling The Deck: ")
deck.show()
deck.mergeSort()
print("After the merge Sort")
deck.show()

Asked By: DANIEL GOLLADAY

||

Source

Answer 1

You’re trying to sort strings. When sorting strings it starts with the first character, and then moves on to the next character if necessary. ‘AZ’ goes before ‘B’ because an ‘A’ is less than ‘B’. The same thing happens when you have a ’10’. It starts by comparing the ‘1’ which goes before everything else in your deck of cards. If you only had integers you would be able to use my_list.sort(key=int), but when you have a mix of integers and characters you need to do something else. Natural sort is one way of solving this issue, however, there is a simpler approach we can use since we have a small finite number of items that we are sorting. What we can do instead is create a list that has all of the card values in the order that we want them to be in, and then we refer back to that list in the key function passed to sort, like so:

def sort_cards(cards):
    card_order = ['2', '3', '4', '5', '6', '7', '8', '9', '10', 'J', 'Q', 'K', 'A']
    return sorted(cards, key=lambda card: card_order.index(card.value))

my_cards = ['10', '5', 'A', '7', 'K']
print(sort_cards(my_cards))

Outputs

[‘5’, ‘7’, ’10’, ‘K’, ‘A’]

Answered By: hostingutilities.com

Answer 2

you can try this

b=[2,3,4,5,6,7,8,9,10,'J','Q','K','A']
sorted(b, key=lambda i: (isinstance(i, int), i), reverse=True)

print(sorted(b, key=lambda i: (isinstance(i, int), i)))

Answered By: Bhar Jay

Sorting an array of Objects (Deck of Cards)

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