Greeting, why is
for number in content: if number != 237: print(number) else: break
working code, but
for number in content: print(number) if number != 237 else break
has an error: expected expression after the inline else?
this is invalid syntax, to put this into prospective, this is the correct usage of the inline if
for i in range(5): foo = 5 if i == 1 else 4
in this code, foo will be assigned the value of 5 or 4, but what about the next code
for i in range(5): foo = 5 if i == 1 else break
what will be the value of foo when this code executes ? break returns nothing, its a language statement, so this is invalid syntax.
and your code is exactly the same, it just doesn’t store the result anywhere, it’s still bound to the same syntax rules, and while print(number) actually returns an object in python 3 (a None is a python object), break doesn’t.