Getting False with my Def, What is wrong with my code?

Question

def richNumber(n):
    nb = []
    n = int(n)
    sum1 = 0
    for i in range(n, n+1):
        if n % i ==0:
            nb.append(i)
    sum1 = sum(nb) - nb[-1]
    if sum1 > n:
        return True
    else:
        return False

n = int(input("n:"))

print(richNumber(n))

I have 5 Test Cases:

n = 4
n = 12
n = 6
n = 20
n = 100

With n = 4 and 6 the output is false ,with n = 12,20,100 is supposed to be true but its showing false.

This function used to get all divisor of n in a list, if the sum of all divisor of n (not N) is larger than N is true, smaller is False

Asked By: Minh

||

Source

Answer 1

for i in (n, n+1)

Iterates over two numbers, n and n + 1, not all divisors. You need to use range to iterate from 1 to n

for i in range(1, n + 1)

Answered By: Guy

Answer 2

Your current richNumber function will always return False because sum1 will
always be 0. Try the following code:

def richNumber(n):
    nb = []
    n = int(n)
    sum1 = 0
    for i in range(1, n):
        if n % i == 0:
            nb.append(i)
    sum1 = sum(nb)
    if sum1 > n:
        return True
    else:
        return False

Answered By: Zeltaat

Getting False with my Def, What is wrong with my code?

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