# Count First number of all lists in list

## Question:

I have a txt file and data in it like this:

```
[1, 2, 1]
[2, 1, 3]
[3, 2, 3]
```

I want to count all lists 1 numbers and write, after this count all second numbers.

Result should be like this.

- Column

1 Result : 1

2 Result : 1

3 Result : 1

- Column

1 Result : 1

2 Result : 2

3 Result : 0

I can’t do it, i try many loops, may you help me pls

My code is like this

```
from ast import literal_eval
count = 0
first = 0
second = 0
third = 0
with open("data.txt") as f:
matrix = []
for line in f:
row = literal_eval(line)
matrix.append(row)
print(matrix)
print(len(matrix))
print("-----------")
for i in matrix:
for j in range(3):
if i[j] == 1:
first += 1
elif i[j] == 2:
second += 1
elif i[j] == 3:
third += 1
print(f"1. Result {first}")
print(f"2. Result {second}")
print(f"3. Result {third}")
print(f"----")
```

## Answers:

Use `zip`

to convert the columns to rows so you can use `count`

on them

```
matrix = [[1, 2, 1],
[2, 1, 3],
[3, 2, 3]]
for t in zip(*matrix):
print(f"1. Result {t.count(1)}")
print(f"2. Result {t.count(2)}")
print(f"3. Result {t.count(3)}")
print(f"----")
```

Output

```
1. Result 1
2. Result 1
3. Result 1
----
1. Result 1
2. Result 2
3. Result 0
----
1. Result 1
2. Result 0
3. Result 2
```