# I get an int error when trying to run a simple addition calculator i made in python

## Question:

When trying to run this simple calculator with only addition and passing "1 + 2" in the terminal without quotes

```
numbers=["1","2","3","4","5","6","7","8","9"]
str=input()
numlist = str.split()
for i in range(len(numlist)):
number=""
operate=""
for j in numlist[i]:
if j in numbers:
number=number+j
else:
operate=operate+j
if operate == "+":
sum = 0
for i in range(len(numlist)):
sum = sum + int(number)
```

it results In this

```
Exception has occurred: ValueError
invalid literal for int() with base 10: ''
File "C:UsersdummyDesktopNew Text Document.py", line 15, in <module>
sum = sum + int(number)
```'
Any help would be appreciated
```

## Answers:

Each time you iterate through numlist you are resetting `number`

to an empty string. I’d suggest moving that and sum above your for loop to make sure they are not reset on each iteration.

```
numbers = ["1", "2", "3", "4", "5", "6", "7", "8", "9"]
given_input = input()
numlist = given_input.split()
number = ""
operate = ""
sum = 0
for i in numlist:
for j in i:
if j in numbers:
number = j
else:
operate = j
if operate == "+" and number != "":
sum += int(number)
number = ""
print(sum)
```