# I need to get line numbers of a standard output

## Question:

I found a solution of a problem and is a recursive function that gives me multiple combinations of numbers like:

- 2 2 3
- 2 4 2
- 2 3 3
- 2 2 4

and I need to find the number of combinations that the functions provides me but the function uses a print to return the values and I cannot find a way to count the number of lines of the output which gives me the solution.

Thanks!

code:

```
def box_extraction(vec, index, target, reducedNum):
if (reducedNum < 0):
return
if (reducedNum == 0):
for i in range(index):
print(vec[i], end = " ")
print("")
return
prev = 1 if(index == 0) else vec[index - 1]
for k in [2,3,4]:
vec[index] = k
box_extraction(vec, index + 1, target, reducedNum - k)
def findSums(n):
vector = [0] * n
box_extraction(vector, 0, n, n)
n = 8;
findSums(n)
```

## Answers:

Assuming you can’t just change the original function, you could always capture the data output to stdout into a list then work with the list, something like:

```
from unittest.mock import patch
from io import StringIO
def fn(a, b, c):
print(a, b, c)
def do():
l = []
with patch('sys.stdout', new=StringIO()) as output:
fn(2, 3, 4)
l.append(output.getvalue())
print(f'Captured output: {l}')
do()
```

You can get the number of combinations by converting the functions to a generator as follows.

**Code**

```
def box_extraction(vec, index, target, reducedNum):
if (reducedNum < 0):
return
if (reducedNum == 0):
result = [vec[i] for i in range(index)]
#for i in range(index):
# print(vec[i], end = " ")
#print("")
yield result
prev = 1 if(index == 0) else vec[index - 1]
for k in [2,3,4]:
vec[index] = k
yield from box_extraction(vec, index + 1, target, reducedNum - k)
def findSums(n):
vector = [0] * n
yield from box_extraction(vector, 0, n, n)
```

**Usage**

```
n = 8;
# To get the number of items:
print(f"Number of items: {len(list(findSums(n)))}")
print("items with an index")
# To generate result with an index
for i, result in enumerate(findSums(n), start = 1):
print(f"{i}: {' '.join(str(x) for x in result)}")
```

**Output**

```
Number of items: 8
items with an index
1: 2 2 2 2
2: 2 2 4
3: 2 3 3
4: 2 4 2
5: 3 2 3
6: 3 3 2
7: 4 2 2
8: 4 4
```