Why this function returns only a digit 2 instead of numbers from 1 to 100?

Question

def display_even_digits(a, b):
    for digit in range(a, b):
        if digit % 2 == 0:
            return digit

print(display_even_digits(1, 101))

Asked By: Keldro

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Source

Answer 1

You are returning the first even number, you need to return all numbers. You could just find if a is even and if not add 1 and then use the step argument of range.

def display_even_digits(a, b):
    return list(range(a + a % 2, b, 2))

print(display_even_digits(1, 101))

[2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24, 26, 28, 30, 32, 34, 36, 38, 40, 42, 44, 46, 48, 50, 52, 54, 56, 58, 60, 62, 64, 66, 68, 70, 72, 74, 76, 78, 80, 82, 84, 86, 88, 90, 92, 94, 96, 98, 100]

Answered By: Jab

Answer 2

This is probably what you want?

def display_even_digits(a, b):
    result = []
    for digit in range(a, b):
        if digit % 2 == 0:
            result.append(digit)
    return result

print(display_even_digits(1, 101))

[2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24, 26, 28, 30, 32, 34, 36, 38, 40, 42, 44, 46, 48, 50, 52, 54, 56, 58, 60, 62, 64, 66, 68, 70, 72, 74, 76, 78, 80, 82, 84, 86, 88, 90, 92, 94, 96, 98, 100]

Answered By: Yu-Fen

Why this function returns only a digit 2 instead of numbers from 1 to 100?

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