Extracting coefficients in sympy is only working for certain symbols

Question

If I define the following equation

import sympy as sp

x00, x01, x02 = sp.symbols('x_{00} x_{01} x_{02}')
x10, x11, x12 = sp.symbols('x_{10} x_{11} x_{12}')
x20, x21, x22 = sp.symbols('x_{20} x_{21} x_{22}')

px0, px1, px2 = sp.symbols('p_{x0} p_{x1} p_{x2}')
py0, py1, py2 = sp.symbols('p_{y0} p_{y1} p_{y2}')

Z = sp.Matrix([ [x00, x01, x02],
                [x10, x11, x12],
                [x20, x21, x22]])
px = sp.Matrix([px0, px1, px2])
py = sp.Matrix([py0, py1, py2])

expr = (py.T * Z * px)[0, 0]

print(expr.coeff(x00))
print(expr.coeff(px0))

I get the output

0
p_{y0}*x_{00} + p_{y1}*x_{10} + p_{y2}*x_{20}

Why is sympy returning the correct output for px0 but not for x00?

Asked By: TheIdealis

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Source

Answer 1

You need to expand before calling coeff:

In [20]: x, y, z = symbols('x, y, z')

In [12]: expr = x*(y + z)

In [13]: expr
Out[13]: x⋅(y + z)

In [14]: expr.coeff(x)
Out[14]: y + z

In [15]: expr.coeff(y) # y does not appear at top level
Out[15]: 0

In [16]: expr.expand() # Now y and z are at top level
Out[16]: x⋅y + x⋅z

In [17]: expr.expand().coeff(x)
Out[17]: y + z

In [18]: expr.expand().coeff(y)
Out[18]: x

In [19]: expr.expand().coeff(z)
Out[19]: x

Answered By: Oscar Benjamin

Answer 2

It is also possible to find the term(s) of interest without having to do a full expansion by replacing products that are not of interest with 0:

>>> (2*x00+expr).replace(lambda x:x.is_Mul, lambda x: x if x.has_free(x00) else 0)
p_{x0}*p_{y0}*x_{00} + 2*x_{00}
>>> _.coeff(x00)
p_{x0}*p_{y0} + 2

Answered By: smichr

Extracting coefficients in sympy is only working for certain symbols

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