How to convert comma separated string to list that contains comma in items in Python?

You can split on separators that contain more than one character. '"coffee", "water, hot"'.split('", "') gives ['"coffee','water, hot"']. From there you can remove the initial and terminal quote mark.

You can almost use csv for this:

import csv
from io import StringIO
sio = StringIO()
sio.write('"coffee", "water, hot"')
sio.seek(0)
reader = csv.reader(sio)
print(next(reader))
# Prints ['coffee', ' "water', ' hot"']

The problem is that there is a space before the opening quote of "water, hot". If you replace '", "' with ",", then csv will work, and you will get ['coffee', 'water, hot'].

Firstly, I defined a function ‘del_quote’ to remove unnecessary quotes and spaces.
Then I split it taking ‘",’ as a separator. then the result was mapped to remove quotes then converted into list.

def del_quote(s):
return s.replace('"','').strip()

x='"coffee", "water, hot"'
result=list(map(del_quote,x.split('",')))
print(result)

How about:

string = '"coffee", "water, hot"'

stringList = string.split("'")

string = stringList[0]

print(string)

You can use re.findall

import re

s = '"coffee", "water, hot"'
re.findall('"(.*?)"', s) # ['coffee', 'water, hot']