Is there a function for changing all row values in a numpy array?
Question:
I have got a 5 by 5 numpy array and a list of 3 values
a = np.array[([[0,4,5,8,2],
[2,3,4,1,3],
[2,3,4,1,3],
[2,3,4,1,3],
[2,3,4,1,3]])
BC = np.array([0,3,4])
with this condition, every row and column of the BC must be 0. In this case, the first, fourth and fifth row and column. The output therefore needs to be
[0,0,0,0,0
0,3,4,0,0
0,3,4,0,0
0,0,0,0,0
0,0,0,0,0]
Of course it is possible to do a[0,0] = 0 and then for every place in the matrix, but I want to use a for loop because the original matrix is 12*12. Thanks for your help!
Answers:
you just have to slice the array then assign it to zeros as follows:
a = np.array[([[0,4,5,8,2],
[2,3,4,1,3],
[2,3,4,1,3],
[2,3,4,1,3],
[2,3,4,1,3]])
BC = np.array([0,3,4])
a[BC,:] = 0
a[:,BC] = 0
[BC,:] losely translates to "indicies of rows as in BC and all columns".
I have got a 5 by 5 numpy array and a list of 3 values
a = np.array[([[0,4,5,8,2],
[2,3,4,1,3],
[2,3,4,1,3],
[2,3,4,1,3],
[2,3,4,1,3]])
BC = np.array([0,3,4])
with this condition, every row and column of the BC must be 0. In this case, the first, fourth and fifth row and column. The output therefore needs to be
[0,0,0,0,0
0,3,4,0,0
0,3,4,0,0
0,0,0,0,0
0,0,0,0,0]
Of course it is possible to do a[0,0] = 0 and then for every place in the matrix, but I want to use a for loop because the original matrix is 12*12. Thanks for your help!
you just have to slice the array then assign it to zeros as follows:
a = np.array[([[0,4,5,8,2],
[2,3,4,1,3],
[2,3,4,1,3],
[2,3,4,1,3],
[2,3,4,1,3]])
BC = np.array([0,3,4])
a[BC,:] = 0
a[:,BC] = 0
[BC,:] losely translates to "indicies of rows as in BC and all columns".