why is not python regex code not working?

Question

I have pasted to code in which I have used regex library in python, while to work on regex I typecasted the x and y variable(in individual scripts) as string to work with regex functions but then also I’m unable to use that variable.

import re
field_value="CREDIT MEMO SHHAA00172362/AB2"
field_value=field_value.replace("CREDIT MEMO ","")
x=re.findall("/.*",field_value)
print(x)
if x:
  field_value=re.sub(str(x),"",field_value)
  print(field_value)

Why is the str type casting is not working on list x?

#Similarly:

import re
field_value='SICR-2205-11-0-00045-1'
y=re.findall('^[A-Z][A-Z][A-Z][A-Z]',field_value)
if y:
  print(y)
  x=re.split("-",field_value,1)
  print(x[0])
  print(x[2])
  if x[0] == str(y):
    print('123')

Why the str type casting is not working on list y?

Asked By: Safeer Khan

||

Source

Answer 1

The method re.findall() always returns an array, even if it is empty or just contains one element.

So str(y) becomes the string "['SICR']".

If what you actually want to compare is the first match re.findall('^[A-Z][A-Z][A-Z][A-Z]',field_value) comes up with (in this case, "SICR") with x[0], then you actually want to do:

if x[0] == y[0]:
    print('123')

Since y[0] is the first match re.findall() found.

Answered By: Aidan Wansbrough

why is not python regex code not working?

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