How to find multiple values on three parallel arrays using count occurence algorithm

Question

I have to find the number of pupils who achieved 75% or more in three different exams. I wrote the code in two different versions where version 2 is successful but I am unable to find the correct value from version 1.

Version 1

literacy = [42,72,80,82,76]
numeracy = [55,70,75,79,48]
technology = [77,64,55,82,52]

count = 0

for counter in range(len(literacy)):
  if literacy[counter] >= 75 and numeracy[counter] >= 75 and technology[counter] >= 75:
    count = count + 1
        

print(count)

output (should result 7)

second version

literacy = [42,72,80,82,76]
numeracy = [55,70,75,79,48]
technology = [77,64,55,82,52]

count = 0

for counter in range(len(literacy)):
  if literacy[counter] >= 75:
    count = count + 1
  if numeracy[counter] >= 75:
    count = count + 1
  if technology[counter] >= 75:
    count = count + 1
        
print(count)

output

Any advise how to fix the first version.

Asked By: John

||

Source

Answer 1

For the first version, It’s iterated only 5 times so if you increment values by 1 you will not get the expected result 7. So the fixing of first version is your second version itself.

Here is another attempt from me.

count = 0
for i in literacy + numeracy + technology:
    if i >= 75:
        count = count + 1

In one line code,

In [1]: len([i for i in literacy + numeracy + technology if i >= 75])
Out[1]: 7

Answered By: Rahul K P

How to find multiple values on three parallel arrays using count occurence algorithm

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