Python. How to sum each element with multi times in loop?

Question

Example:

import numpy
a = [1,2,3,4,5]
b = []
for i in range(len(a)):
    b.append(a[i]+1)

Here, I have b = [2,3,4,5,6].
But I want sum multi times…(maybe I want to sum with 3 times). I expected after three times sum I have b = [4,5,6,7,8].

So, how I can get b=[4,5,6,7,8] from a=[1,2,3,4,5] with 3 times add 1 with loop?

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Answer 1

Add 3 to each element using a list comprehension;

b = [i+3 for i in a]

or as a function, where you can change the value added to the list easily;

def add_k_to_list(k, a_list):
    return [i+k for i in a_list]

To repeatedly apply as per your comment;

def add_k_to_list(k, a_list):
    for _ in range(k):
        a_list = [i+1 for i in a_list]
    return(a_list)

Answered By: bn_ln

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