Python regex match the third line containing a float
Question:
I have a list containing those 3 lines repeated n times:
Test
Choice : Q1
Expected : 0,5
The only value that differ into the list is the third line Expected : 0,5 the float number can differ from -10 to 10.
I haven’t managed to come up with a regular expression to only get the float number inside the third line yet.
I’m not comfortable with regex, what I’ve managed to dot yet is something like this:
(?:^[^n]*n?)
Here is my regex demo.
Any good suggestion?
Answers:
You can use
b[0-9]+(?:,[0-9]+)?b
See the regex demo.
Details:
b – a word boundary[0-9]+ – one or more digits(?:,[0-9]+)? – an optional sequence of a comma and one or more digitsb – a word boundary
You don’t need a regex for a simple task like this:
>>> s = 'Expected : 0,5'
>>> value = s.split(':')[-1].strip()
>>> value
'0,5'
If you want it to be a float rather than a string:
>>> num_value = float(value.replace(',', '.'))
>>> num_value
0.5
I have a list containing those 3 lines repeated n times:
Test
Choice : Q1
Expected : 0,5
The only value that differ into the list is the third line Expected : 0,5 the float number can differ from -10 to 10.
I haven’t managed to come up with a regular expression to only get the float number inside the third line yet.
I’m not comfortable with regex, what I’ve managed to dot yet is something like this:
(?:^[^n]*n?)
Here is my regex demo.
Any good suggestion?
You can use
b[0-9]+(?:,[0-9]+)?b
See the regex demo.
Details:
b– a word boundary[0-9]+– one or more digits(?:,[0-9]+)?– an optional sequence of a comma and one or more digitsb– a word boundary
You don’t need a regex for a simple task like this:
>>> s = 'Expected : 0,5'
>>> value = s.split(':')[-1].strip()
>>> value
'0,5'
If you want it to be a float rather than a string:
>>> num_value = float(value.replace(',', '.'))
>>> num_value
0.5