I tried a make a calculator but it gives an error

Question

Hi I’m new at the python and trying to make basic calculator, but when i try to start it gives a string is not int error, can u help me please?

def Add(number1, number2):
    return number1+number2
    
def Minus (number1, number2):
    return number1-number2
    
def Multiply (number1, number2):
    return number1*number2
    
def Divide (number1, number2):
    return number1/number2
    
print("Operation?")
print("1: Add")
print("2: Minus")
print("3: Multiply")
print("4: Divide")

operation= int(input("Please selecet an operation..."))
number1= int(input("Enter Number1"))
number2= int(input("Enter Number2"))

if operation==1:
    print("Answer= "+ int(number1+number2))
elif operation==2:
    print("Answer= "+ int(number1-number2))
elif operation==3:
    print("Answer= "+ int(number1*number2))
elif operatipn==4:
    print("Answer= "+ int(number1/number2))
else:
    print("You didn't choose anything in list")

Asked By: Muhammet AYDIN

||

Source

Answer 1

The problem here is that you are trying to add an int object to a str object in the print statements:

print("Answer= "+ int(number1-number2))

you just need to convert it to str not an int because the result of the – or + operations on int objects will be int:

print("Answer= "+ str(number1-number2))

Answered By: Bemwa Malak

Answer 2

Try using , instead of + :

def Add(number1, number2):
    return number1+number2
    
def Minus (number1, number2):
    return number1-number2
    
def Multiply (number1, number2):
    return number1*number2
    
def Divide (number1, number2):
    return number1/number2
    
print("Operation?")
print("1: Add")
print("2: Minus")
print("3: Multiply")
print("4: Divide")

operation= int(input("Please selecet an operation..."))
number1= int(input("Enter Number1"))
number2= int(input("Enter Number2"))

if operation==1:
    print("Answer= ", int(number1+number2))
elif operation==2:
    print("Answer= ", int(number1-number2))
elif operation==3:
    print("Answer= ", int(number1*number2))
elif operatipn==4:
    print("Answer= ", int(number1/number2))
else:
    print("You didn't choose anything in list")

Answered By: Battseren Badral

Answer 3

You can solve the above question in below following way as well without if condition

Dictionary is most powerful in this case when you don’t want to write 'N' number of times the if statements

First way :

def Add(number1, number2):
    return number1+number2
    
def Minus (number1, number2):
    return number1-number2
    
def Multiply (number1, number2):
    return number1*number2
    
def Divide (number1, number2):
    return number1/number2

number1 = int(input('Enter number 1 : '))
number2 = int(input('Enter number 2 : '))

myuserinput = int(input('Enter the option : '))

myoption = { 1 : Add(number1, number2) , 2 : Minus(number1, number2) , 3 : Multiply(number1, number2) , 4:Divide (number1, number2) } 


myoption.get(myuserinput,'Please provide proper input')

Second way :

def Add(number1, number2):
    result = number1 + number2 
    return 'Answer : {0}'.format(result)
    
def Minus (number1, number2):
    result = number1 - number2 
    return 'Answer : {0}'.format(result)
    
def Multiply (number1, number2):
    result = number1 * number2 
    return 'Answer : {0}'.format(result)
    
def Divide (number1, number2):
    result = number1 / number2 
    return 'Answer : {0}'.format(result)

number1 = int(input('Enter number 1 : '))
number2 = int(input('Enter number 2 : '))

myuserinput = int(input('Enter the option : '))

myoption = { 1 : Add(number1, number2) , 2 : Minus(number1, number2) , 3 : Multiply(number1, number2) , 4:Divide (number1, number2) } 


myoption.get(myuserinput,'Please provide proper input')

Answered By: codeholic24

Answer 4

With print you should type a coma "," instead of "+"

print("Answer= ", int(number1+number2))

Try it and see, if it doesn’t work then try removing int() from your prints!

 print("Answer= ", number1+number2)

Good luck!

Answered By: user20165318

I tried a make a calculator but it gives an error

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