Django Error: init() takes 1 positional argument but 2 were given

Question

I am new to Django and I’m trying to create my first project following a tutorial from Udemy, but I encounter this error.

My project has the following folder structure:

-demo

__ init__.py
admin.py
apps.py
models.py
tests.py
urls.py
-views.py

-first

__ init__.py
asgi.py
settings.py
urls.py
wsgi.py

views.py:

from django.shortcuts import render
from django.http import HttpRequest


def first(request):
    return HttpRequest('1st message from views')

demo/urls.py:

from django.urls import path
from . import views

urlpatterns = [
    path('', views.first),
]

first/urls.py:

from django.contrib import admin
from django.urls import path, include

urlpatterns = [
    path('demo/', include('demo.urls')),
    path('admin/', admin.site.urls),
]

Both __ init__.py files are empty

error:

TypeError at /demo/
__init__() takes 1 positional argument but 2 were given
Request Method: GET
Request URL:    http://127.0.0.1:8000/demo/
Django Version: 3.2.16
Exception Type: TypeError
Exception Value:    
__init__() takes 1 positional argument but 2 were given
Exception Location: D:PythonDJANGOfirst-projectdemoviews.py, line 6, in first
Python Executable:  D:PythonDJANGOfirst-projectvenvScriptspython.exe
Python Version: 3.7.6
Python Path:    
['D:\Python\DJANGO\first-project',
 'D:\Python\DJANGO\first-project',
 'C:\Users\biavu\AppData\Local\Programs\Python\Python37\python37.zip',
 'C:\Users\biavu\AppData\Local\Programs\Python\Python37\DLLs',
 'C:\Users\biavu\AppData\Local\Programs\Python\Python37\lib',
 'C:\Users\biavu\AppData\Local\Programs\Python\Python37',
 'D:\Python\DJANGO\first-project\venv',
 'D:\Python\DJANGO\first-project\venv\lib\site-packages']
Server time:    Thu, 06 Oct 2022 12:34:45 +0000

Asked By: Vulsan Bianca

||

Source

Answer 1

You need to return a HttpResponse, not HttpRequest.

A request is what you get as input.

from django.http import HttpResponse

def first(request):
    return HttpResponse('1st message from views')

Answered By: AKX

Answer 2

This Answer worked for me, i had used HttpRequest instead of HttpResponse.

A request is what you get as input.

from django.http import HttpResponse

def first(request):
return HttpResponse(‘1st message from views’)

Answered By: Julius Kamya

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