is there a more efficient way to make a grid for bool values

Question

I am trying to make a grid to store bool variables kinda like mine sweeper and i would like to find a better way
So far i have a very inefficient way of just declaring like 15 lists with the values set to false like this

A = [False, False, False, False, False, False, False, False, False, False]

Is there a more efficient way to do this

Asked By: caleb yoshihara

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Source

Answer 1

You can efficiently create a list of the same value with:

A = [False]*15

However, more code is required to extend this into a grid. Instead, you could use NumPy to create a grid of False (True) values by using np.zeros (np.ones). For example, a 3×4 grid of False values can be created with:

grid = np.zeros((3, 4), dtype=bool)

>> [[False False False False]
>>  [False False False False]
>>  [False False False False]]

Answered By: Kieran

Answer 2

You might want to use a 2D array for that:

array = [
    [False, False, False, False, False, False, False, False, False, False],
    [False, False, False, False, False, False, False, False, False, False],
    ...
]

This can also be created using a list comp:

array = [[False] * 15 for _ in range(15)]

Answered By: Tantary Tauseef

Answer 3

One liner:

array = [[False] * 15 for _ in range(15)]

Answered By: Suhaib

is there a more efficient way to make a grid for bool values

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