how to write method/function named movel( s, k) that moves all the elements of the 's' array to the left by 'k' positions (not rotate)?
Question:
this is my code below and please help me find out the the expected output[ 4,5,6,0,0,0]
def movel(s, k):
n=len(s)
j=0
n_arr=s[:k]
return (s[k::]+n_arr[::])
for j in range(0, n):
print(s[j], end=' ')
s=[1,2,3,4,5,6]
k=3
movel(s,k)
*Output : [4,5,6,1,2,3] *
Answers:
You could do use index slicing
def movel(s, k):
if k > len(s):
return [0] * len(s) # you decide how to handle this case
return s[k:] + [0] * (len(s) - k)
Think of it this way, we change the head of the list and fill the rest with zeros.
this is my code below and please help me find out the the expected output[ 4,5,6,0,0,0]
def movel(s, k):
n=len(s)
j=0
n_arr=s[:k]
return (s[k::]+n_arr[::])
for j in range(0, n):
print(s[j], end=' ')
s=[1,2,3,4,5,6]
k=3
movel(s,k)
*Output : [4,5,6,1,2,3] *
You could do use index slicing
def movel(s, k):
if k > len(s):
return [0] * len(s) # you decide how to handle this case
return s[k:] + [0] * (len(s) - k)
Think of it this way, we change the head of the list and fill the rest with zeros.