Regex to match phone number 5ABXXYYZZ
Question:
I am using regex to match 9 digits phone numbers.
I have this pattern 5ABXXYYZZ that I want to match.
What I tried
I have this regex that matches two repetitions only 5ABCDYYZZ
S_P_2 = 541982277
S_P_2_pattern = re.sub(r"(?!.*(d)1(d)2(d)3).{4}d(d)4(d)5", "Special", str(S_P_2))
print(S_P_2_pattern)
What I want to achieve
I would like to update it to match three repetitions 5ABXXYYZZ sample 541882277
Answers:
Try:
^5dd(?:(d)1(?!.*1)){3}$
See an online demo
^5dd – Start-line anchor and literal 5 before two random digits;(?:(d)1(?!.*1)){3} – Non-capture group matched three times with nested capture group followed by itself directly but (due to negative lookahead) again after 0+ chars;$ – End-line anchor.
I am using regex to match 9 digits phone numbers.
I have this pattern 5ABXXYYZZ that I want to match.
What I tried
I have this regex that matches two repetitions only 5ABCDYYZZ
S_P_2 = 541982277
S_P_2_pattern = re.sub(r"(?!.*(d)1(d)2(d)3).{4}d(d)4(d)5", "Special", str(S_P_2))
print(S_P_2_pattern)
What I want to achieve
I would like to update it to match three repetitions 5ABXXYYZZ sample 541882277
Try:
^5dd(?:(d)1(?!.*1)){3}$
See an online demo
^5dd– Start-line anchor and literal 5 before two random digits;(?:(d)1(?!.*1)){3}– Non-capture group matched three times with nested capture group followed by itself directly but (due to negative lookahead) again after 0+ chars;$– End-line anchor.