Python Index Nested Dictionary with List

Question

If I have a nested dictionary and varying lists:

d = {'a': {'b': {'c': {'d': 0}}}}
list1 = ['a', 'b']
list2 = ['a', 'b', 'c']
list3 = ['a', 'b', 'c', 'd']

How can I access dictionary values like so:

>>> d[list1]
{'c': {'d': 0}}
>>> d[list3]
0

Asked By: Oliver

||

Source

Answer 1

you can use functools reduce. info here. You have a nice post on reduce in real python

from functools import reduce

reduce(dict.get, list3, d)
>>> 0

EDIT: mix of list and dictioanries

in case of having mixed list and dictionary values the following is possible

d = {'a': [{'b0': {'c': 1}}, {'b1': {'c': 1}}]}
list1 = ['a', 1, 'b1', 'c']

fun = lambda element, indexer: element[indexer]
reduce(fun, list1, d)
>>> 1

Answered By: Lucas M. Uriarte

Answer 2

Use a short function:

def nested_get(d, lst):
    out = d
    for x in lst:
        out = out[x]
    return out

nested_get(d, list1)
# {'c': {'d': 0}}

Answered By: mozway

Python Index Nested Dictionary with List

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