Python regex to match all occurrences between curly brackets, not just the last occurence
Question:
In my Python code, I have the following string:
Here is my string with ""The Address", I want to replace only the selection between the brackes: {Here is my string between "The Address" and "something" else}. Thank you!
I would like to replace ALL occurrences of " that occur ONLY between curly brackets with ". So my desired result is
Here is my string with ""The Address", I want to replace only the selection between the brackes: {Here is my string between "The Address" and "something" else}. Thank you!
I’m trying r'({.*)(\")(.*})' with a substitution of 1"3 as given here: https://regex101.com/r/NWSDS6/1
However that is only selecting/replacing the very last " , how do I select/replace ALL of the occurrences between the curly braces?
EDIT after comment: Here is a variation of the string with an extra curly bracket after the word "replace":
Here is my string with ""The Address", I want to replace} only the selection between the brackes: {Here is my string between "The Address" and "something" else}. Thank you!
In this variation, the first two occurrences are selected however I would like them to be omitted as they do not occur BETWEEN TWO curly brackets. Is that possible?
Answers:
You can use this solution using lambda:
s = r'Here is my string with ""The Address", I want to replace} only the selection between the brackes: {Here is my string between "The Address" and "something" else}. Thank you!'
s = re.sub(r'{[^}]*}', lambda m: m.group().replace(r'"', '"'), s)
console.log(s)
Output:
Here is my string with ""The Address", I want to replace} only the selection between the brackes: {Here is my string between "The Address" and "something" else}. Thank you!
Here:
{[^}]*} matches string between {...}m.group().replace(r'"', '"') replaces all " with " inside the matched text.
In my Python code, I have the following string:
Here is my string with ""The Address", I want to replace only the selection between the brackes: {Here is my string between "The Address" and "something" else}. Thank you!
I would like to replace ALL occurrences of " that occur ONLY between curly brackets with ". So my desired result is
Here is my string with ""The Address", I want to replace only the selection between the brackes: {Here is my string between "The Address" and "something" else}. Thank you!
I’m trying r'({.*)(\")(.*})' with a substitution of 1"3 as given here: https://regex101.com/r/NWSDS6/1
However that is only selecting/replacing the very last " , how do I select/replace ALL of the occurrences between the curly braces?
EDIT after comment: Here is a variation of the string with an extra curly bracket after the word "replace":
Here is my string with ""The Address", I want to replace} only the selection between the brackes: {Here is my string between "The Address" and "something" else}. Thank you!
In this variation, the first two occurrences are selected however I would like them to be omitted as they do not occur BETWEEN TWO curly brackets. Is that possible?
You can use this solution using lambda:
s = r'Here is my string with ""The Address", I want to replace} only the selection between the brackes: {Here is my string between "The Address" and "something" else}. Thank you!'
s = re.sub(r'{[^}]*}', lambda m: m.group().replace(r'"', '"'), s)
console.log(s)
Output:
Here is my string with ""The Address", I want to replace} only the selection between the brackes: {Here is my string between "The Address" and "something" else}. Thank you!
Here:
{[^}]*}matches string between{...}m.group().replace(r'"', '"')replaces all"with"inside the matched text.