Python – how can I print n numbers per line of range by using for loop?

solution

sum=0
for i in range(2,1001,2):
    sum+=i
    if i%20 == 2: print("n{}".format(i),end="")    # print new line per 20 numbers
    else: print(", {}".format(i),end="")
print("nSum of all even numbers within 1 and 1000 =",sum)

• Output:

  2, 4, 6, 8, 10, 12, 14, 16, 18, 20 
  22, 24, 26, 28, 30, 32, 34, 36, 38, 40 
  ...
  962, 964, 966, 968, 970, 972, 974, 976, 978, 980 
  982, 984, 986, 988, 990, 992, 994, 996, 998, 1000
  Sum of all even numbers within 1 and 1000 = 250500
  

another solution with better run time performance

print("".join(["n"+str(i) if i%20==2 else ", "+str(i) for i in range(2,1001,2)]))
print("nSum of all even numbers within 1 and 1000 =",sum(range(2,1001,2)))

Uisng textwrap Inbuilt Library

import textwrap
import re

sum=0
sq=""


for i in range (0+2,1000+1,2):
   sum+=i
   if i<1000:
      sq=sq+str(i)+","
    
   else:
      sq=sq+str(i)
#print(sq, end="n")

print('n'.join(textwrap.wrap(sq, 20)))#Mask n here

      
print("Sum of all even numbers within 1 and 1000 =",sum)

#output

2,4,6,8,10,12,14,16,18,20,22,24,26,28,30
,32,34,36,38,40,42,44,46,48,50,52,54,56,
58,60,62,64,66,68,70,72,74,76,78,80,82,8
4,86,88,90,92,94,96,98,100,102,104,106,1
08,110,112,114,116,118,120,122,124,126,1
28,130,132,134,136,138,140,142,144,146,1
48,150,152,154,156,158,160,162,164,166,1
68,170,172,174,176,178,180,182,184,186,1
88,190,192,194,196,198,200,202,204,206,2
08,210,212,214,216,218,220,222,224,226,2
28,230,232,234,236,238,240,242,244,246,2
48,250,252,254,256,258,260,262,264,266,2
68,270,272,274,276,278,280,282,284,286,2
88,290,292,294,296,298,300,302,304,306,3
08,310,312,314,316,318,320,322,324,326,3
28,330,332,334,336,338,340,342,344,346,3
48,350,352,354,356,358,360,362,364,366,3
68,370,372,374,376,378,380,382,384,386,3
88,390,392,394,396,398,400,402,404,406,4
08,410,412,414,416,418,420,422,424,426,4
28,430,432,434,436,438,440,442,444,446,4
48,450,452,454,456,458,460,462,464,466,4
68,470,472,474,476,478,480,482,484,486,4
88,490,492,494,496,498,500,502,504,506,5
08,510,512,514,516,518,520,522,524,526,5
28,530,532,534,536,538,540,542,544,546,5
48,550,552,554,556,558,560,562,564,566,5
68,570,572,574,576,578,580,582,584,586,5
88,590,592,594,596,598,600,602,604,606,6
08,610,612,614,616,618,620,622,624,626,6
28,630,632,634,636,638,640,642,644,646,6
48,650,652,654,656,658,660,662,664,666,6
68,670,672,674,676,678,680,682,684,686,6
88,690,692,694,696,698,700,702,704,706,7
08,710,712,714,716,718,720,722,724,726,7
28,730,732,734,736,738,740,742,744,746,7
48,750,752,754,756,758,760,762,764,766,7
68,770,772,774,776,778,780,782,784,786,7
88,790,792,794,796,798,800,802,804,806,8
08,810,812,814,816,818,820,822,824,826,8
28,830,832,834,836,838,840,842,844,846,8
48,850,852,854,856,858,860,862,864,866,8
68,870,872,874,876,878,880,882,884,886,8
88,890,892,894,896,898,900,902,904,906,9
08,910,912,914,916,918,920,922,924,926,9
28,930,932,934,936,938,940,942,944,946,9
48,950,952,954,956,958,960,962,964,966,9
68,970,972,974,976,978,980,982,984,986,9
88,990,992,994,996,998,1000
Sum of all even numbers within 1 and 1000 = 250500

Also

import textwrap
import re

sum=0
sq=""


for i in range (0+2,1000+1,2):
   sum+=i
   if i<1000:
      sq=sq+str(i)+","
    
   else:
      sq=sq+str(i)
#print(sq, end="n")


print (textwrap.fill(sq, 20))
      
print("Sum of all even numbers within 1 and 1000 =",sum)

#same output

Try this,

lst = [i for i in range(2,1001,2)]
for i in range(0, len(lst), 20):
    print(','.join(str(i) for i in lst[i:i+20]))
print(f'Sum of all even numbers within 1 and 1000 : {sum(lst)}')