How to create a loop if contents of a list is in a variable?

Question

I’m asking the user for a name, and if that name contains a number I want to print that they need to remove the numbers. But I can’t exit the loop afterwards.

    numbers=['1','2','3','4','5','6','7','8','9','0']
    vad2=input("To what site are you going to use the password? ")
    for f in numbers:
        if f in vad2:
            while True:
                print("You can't include numbers in the name of the site.")
                vad2=input("To what site are you going to use the password? ")
                numbers=['1','2','3','4','5','6','7','8','9','0']
                for f in numbers:
                    if f in vad2
                        print()
                    else:
                        break;

The first time I use:

for f in numbers:
   if f in vad2:

It works (the code skips the loop if I don’t include any numbers) but when I do the same thing in the loop it wont work for some reason.

Asked By: CobraCabbe

||

Source

Answer 1

Break will jump over your ‘for loop’, not over your ‘while loop’.
Modify your code like

if not vad2.isalpha():   # if you want only alphabet from your input
    print()

Answered By: Adrien Derouene

How to create a loop if contents of a list is in a variable?

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