Sending a file path from .py to another .py

Question

I’m trying to call a foo.py passing a filePath to bar.py

foo.py

for path in Path('./csvs').rglob('*.csv'):
    exec(open('bar.py').read())
    exec(open('bar2.py').read())
    exec(open('bar3.py').read())

bar.py

df = pd.read_csv(path, usecols=cols)
#rest of code

Is it possible?

Asked By: null92

||

Source

Answer 1

I dont know the exact format of your bar.py, but you can try:

for filePath in Path('./csvs').rglob('*.csv'):
    for i in range(1, 4):
        with open(f`bar{i}.py`) as f;
            bar_py_str = f.read()

        bar_py_str = bar_py_str.replace(
            'df = pd.read_csv(filePath, usecols=cols)',
            f'df = pd.read_csv({str(filePath.resolve()}, usecols=cols)'
        )

        exec(bar_py_str)

Answered By: Tom McLean

Answer 2

After .read()ing a file you’re dealing with a string. So you can .replace() a placeholder.

file1.py:

exec(open("file2.py").read().replace("*place_holder*", "10"))

file2.py:

def fn():
    print("My number is *place_holder*")
fn()

But be careful about what you choose as the placeholder. .replace() will replace all the occurrences.

Of course for more complex replacing you can use regex. It can restrict the search better and safer.

Answered By: S.B

Sending a file path from .py to another .py

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