Print all the "a" of a string on python

Question

I’m trying to print all the "a" or other characters from an input string. I’m trying it with the .find() function but just print one position of the characters. How do I print all the positions where is an specific character like "a"

Asked By: Martí Xuclà

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Source

Answer 1

You can use find with while loop

a = "aabababaa"
k = 0
while True:
    k = a.find("a", k) # This is saying to start from where you left
    if k == -1:
        break
    k += 1
    print(k)

Answered By: Deepak Tripathi

Answer 2

This is also possible with much less amount of code if you don’t care where you want to start.

a = "aabababaa"

for i, c in enumerate(a): # i = Index, c = Character. Using the Enumerate()
  if ("a" in c):
    print(i)

Answered By: ThisQRequiresASpecialist

Answer 3

Some first-get-all-matches-and-then-print versions:

With a list comprehension:

s = "aslkbasaaa"

CHAR = "a"
pos = [i for i, char in enumerate(s) if char == CHAR]
print(*pos, sep='n')

or with itertools and composition of functions

from itertools import compress

s = "aslkbasaaa"

CHAR = "a"
pos = compress(range(len(s)), map(CHAR.__eq__, s))
print(*pos, sep='n')

Answered By: cards

Print all the "a" of a string on python

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