Change days to int without pandas in python

Question

Is there any way to convert the resulting days into INT without pandas? Or use the number of days to do "for" loop?

from datetime import datetime, timedelta

d = datetime.today() - timedelta(days=10) 
date = datetime.today() - d

print(date)

Result:

10 days, 0:00:00

If I try for loop, it doesn’t work.

for days in range(date):
    print("■")

Error:

line 16, in <module>
    for i in range(date):
TypeError: 'datetime.timedelta' object cannot be interpreted as an integer

Newb, thank you.

Asked By: Sarian Morio

||

Source

Answer 1

You could try

"astype"

date = date.astype(int)

Answered By: 29belgrade29

Answer 2

When you subtract two datetime.datetime objects, the result is a datetime.timedelta. Check out the linked docs page for more information. From the docs:

Instance attributes (read-only):

Attribute Value

days Between -999999999 and 999999999 inclusive

seconds Between 0 and 86399 inclusive

microseconds Between 0 and 999999 inclusive

Accessing the .days attribute gives the number of days as an integer.

So your example should look something like this:

In [1]: from datetime import datetime, timedelta
   ...:
   ...: delta = timedelta(days=10)

In [2]: for days in range(delta.days):
   ...:     print(days)
   ...:
0
1
2
3
4
5
6
7
8
9

Answered By: Michael Delgado

Change days to int without pandas in python

Question:

Answers:

Attribute	Value
`days`	Between -999999999 and 999999999 inclusive
`seconds`	Between 0 and 86399 inclusive
`microseconds`	Between 0 and 999999 inclusive