Subprocess not opening files

Question

I am writing a program to open other programs for me. os.system() would always freeze my app, so I switched to subprocess.

I did some research and this is how a tutorial told me to open a program.

I have only replaced the path for my variable, which contains the path.

After I run this, only a commabd prompt window opens and nothing else. How can I fix this?

Code:

from subprocess import Popen
filename1 = "C:/Program Files/Google/Chrome/Application/chrome.exe"
Popen(["cmd", "/c", "start", filename1)

Asked By: Tetrapak

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Source

Answer 1

You need to create a single string with double quotes around it. In Python terms, you basically want r'"c:torturethanks Microsoft"' where the single quotes and the r create a Python string, which contains the file name inside double quotes.

from subprocess import Popen

filename1 = "C:/Program Files/Google/Chrome/Application/chrome.exe"
Popen(["cmd", "/c", "start", f'"{filename1}"'])

Quoting with CMD is always bewildering; maybe think about ways you can avoid it (or Windows altogether, if you have a choice).

Answered By: tripleee

Answer 2

import subprocess
filename1 = "C:Program FilesGoogleChromeApplicationchrome.exe"
subprocess.Popen(filename1)

Answered By: Tetrapak

Subprocess not opening files

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