PySpark: Create New Column And Give similar value for each row with similar values of Other Columns

Question

Imagine having the following spark dataframe

+---+----+----+
| Id|A_rk|B_rk|
+---+----+----+
|  a|   5|   4|
|  b|   7|   7|
|  c|   5|   4|
|  d|   1|   0|
+---+----+----+

I want to create a column called Pair that takes the value of B_rk if two rows have the same values for A_rk and B_rk and the value of 0 if there is no match. The result would be:

+---+----+----+----+
| Id|A_rk|B_rk|Pair|
+---+----+----+----+
|  a|   5|   4|   4|
|  b|   7|   7|   0|
|  c|   5|   4|   4|
|  d|   1|   0|   0|
+---+----+----+----+

I had a successful attempt with pandas using for loops. But I want to use spark for better performance.

Asked By: devCharaf

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Source

Answer 1

1.4 million rows is still fine with pandas.

data = [(randint(0, 1000000), randint(0, 100000)) for _ in range(1400000)]
df = pd.DataFrame(data, columns=['A_rk', 'B_rk'])

df['cnt'] = df.groupby(['A_rk', 'B_rk']).transform('size')
df.loc[df.cnt > 1, 'Pair'] = df.B_rk. # or df.cnt == 2 if you only count pair (2 rows exact).
df['Pair'] = df.Pair.fillna(0).astype(int)

I just ran this with 1.4 million rows and ran in less than a second.

389 ms ± 4.77 ms per loop (mean ± std. dev. of 7 runs, 1 loop each)

Pyspark solution:

from pyspark.sql import Window
from pyspark.sql import functions as F
w = Window.partitionBy('A_rk', 'B_rk')
df = (df.withColumn('cnt', F.count('A_rk').over(w))
      .withColumn('Pair', F.when(F.col('cnt') > 1, F.col('B_rk')).otherwise(F.lit(0))))

Answered By: Emma

PySpark: Create New Column And Give similar value for each row with similar values of Other Columns

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