How can I find a word and print it along with his next word in Python

Question

I have the following list:

pre = ["unable to", "would not", "was not", "did not", "there is not", "could not", "failed to"]

From dataframe column I want to find texts that have the words of the list in order to generate a new column that can print these words along with the next word, for example, in a column cell there is the following text WOULD NOT PRIME CORRECTLY DURING VIRECTOMY., I want a new column that prints the following: WOULD NOT PRIME.

I have tried something like this

def matcher(Event_Description):
    for i in pre:
        if i in Event_Description:
            return i + 1
    return "Not found"

Asked By: Victor Leon

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Source

Answer 1

You can loop over every prefix in the list and check for the prefix using .find(). If it is found, you can change the prefix to the case of event and append the next word. Like this:

def matcher(event):
    pres = ["unable to", "would not", "was not", "did not", "there is not", "could not", "failed to"]
    for pre in pres:
        i = event.lower().find(pre)
        if i != -1:
            return ' '.join([pre.upper() if event.isupper() else pre, *event[i + len(pre) + 1:].split(' ')[0]])
    return "Not found"

If you want to include the next two words, just change this line:

return ' '.join([pre.upper() if event.isupper() else pre, *event[i + len(pre) + 1:].split(' ')[0]])

to a slice like this:

return ' '.join([pre.upper() if event.isupper() else pre, *event[i + len(pre) + 1:].split(' ')[0:2]])

Answered By: Michael M.

How can I find a word and print it along with his next word in Python

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